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Algebra

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If f(x) is a monic quartic polynomial such that f(-1)=-1, f(2)=-4, f(-3)=9, and f(4)=-16, find f(1).

May 15, 2022

1+0 Answers

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You can let $$f(x) = x^4 + ax^3 + bx^2 + cx + d$$ be the polynomial. You can then use the given information to find the missing coefficients.

Substituting x = -1, 2, -3, 4 respectively gives $$\begin{cases}1-a+b-c+d = -1\\16 + 8a + 4b + 2c + d = -4\\81 - 27a + 9b - 3c + d = 9\\256 + 64a + 16b + 4c + d = -16\end{cases}$$.

Solving gives:

So f(1) = $$1 + \left(-\dfrac{79}{35}\right) + \left(-\dfrac{89}7\right) + \dfrac{432}{35} + \dfrac{768}{35}$$ = 711/35.

May 15, 2022