First, let's find factors of 12
12=1*12
12=2*6
12=3*4
now let's do trials (I.e. you try these values until you get the answer as they are the only factors of 12)
\((4x-)(3x-)\)
- what??
2*1 as the product of them must be equal to +2 and sum to -11
\((4x-2)(3x-1)\) Notice this doesn't work why? because if you expand it it is not the same. Now let's try to switch 2 and 1
\((4x-1)(3x-2)\) This works!
