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For a real number x, find the number of different possible values of x^2 - abs(x)^2.

 Jul 14, 2021

Best Answer 

 #1
avatar+86 
+3

Answer: \(0\)

 

Solution:

\(x^2\) is always positive. So is the absolute value of x (which is then squared to get \(x^2\)). Since both sides of the expression are \(x^2\), there is only one possible answer for \(x^2-x^2\)\(0\).

 Jul 14, 2021
 #1
avatar+86 
+3
Best Answer

Answer: \(0\)

 

Solution:

\(x^2\) is always positive. So is the absolute value of x (which is then squared to get \(x^2\)). Since both sides of the expression are \(x^2\), there is only one possible answer for \(x^2-x^2\)\(0\).

WhyamIdoingthis Jul 14, 2021

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