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If a + b + c = -3, a+3b+c = 9, a+b+3c = -19, then find abc.

 Jun 15, 2021

Best Answer 

 #1
avatar+39 
+2

1. \(a+b+c=-3\)

2. \(a+3b+c=9\)

3. \(a+b+3c=-19\)

Subsrtacting equation number 1 from equation number 2 we get

\(b=6\)

Substracting equation number 1 from equation number 3 we get

\(c=-8\)

Then putting \(b\) and \(c\) into equation 1

we get

\(a=-1\)

so

\(abc=-1\times-8\times6=\)48

 Jun 15, 2021
 #1
avatar+39 
+2
Best Answer

1. \(a+b+c=-3\)

2. \(a+3b+c=9\)

3. \(a+b+3c=-19\)

Subsrtacting equation number 1 from equation number 2 we get

\(b=6\)

Substracting equation number 1 from equation number 3 we get

\(c=-8\)

Then putting \(b\) and \(c\) into equation 1

we get

\(a=-1\)

so

\(abc=-1\times-8\times6=\)48

FeedMePi Jun 15, 2021
 #2
avatar+121006 
0

Very nice, FMP    !!!!!!

 

 

cool cool cool

 Jun 15, 2021
 #3
avatar+39 
+3

Thanks CPhill

smiley

FeedMePi  Jun 15, 2021

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