First, let's apply some log rules to simplify our equation. We get
\(\log _3\left(x\right)=x\) from this.
We know \(\mathrm{If}\:f\left(x\right)=g\left(x\right),\:\mathrm{then}\:a^{f\left(x\right)}=a^{g\left(x\right)}\)
From this, we have \(3^{\log _3\left(x\right)}=3^x\)
Which is the same as \(x=3^x\)
There are NO SOLUTIONS to this equation.
Thanks! :)
Thanks, NotThat Smart !!!!
\(\log_2 (\log_3 x) = 2 \log_4 (x) \)
To elaborate a little, we can use the change of base theorem to write
log ( logx / log 3 ) 2 log (x)
______________ = ________ { log 4 = log 2^2 = 2log 2 }
log 2 log 4
log ( log x / log 3 ) 2log (x)
______________ = _______
log 2 2log 2
log ( logx / log 3 ) = log (x)
This implies that
logx / log 3 = x
log x = xlog 3
log x = log 3^x
x = 3^x
Note here that the graphs of both functions never intersect
https://www.desmos.com/calculator/82kerdz2ip
So, like NotThatSmart, I don't find any solutions, either !!!