Algebra

Alright. First, let's combine all like terms to this horrible mess. We get that

\(6x^{2}-21x-31=0\)

Now, we simply apply the quadratic formula and take the smaller root. Using the fomrula, we get

\(x=\frac{21\pm \sqrt{(-21)^{2}-4\cdot 6(-31)}}{2\cdot 6}\)

From this monstrosity, we get that

\(x=\frac{\sqrt{1185}+21}{12}\\ x=\frac{-\sqrt{1185}+21}{12}\)

Obviously, the first term of x is bigger, so we take that as our answer. 

We find that x is \(x=\frac{\sqrt{1185}+21}{12}\)

So our answer is just the biiger root. 

Thanks! :)

also, 500th answer...woop woop! :)