+826 Find the largest value of $x$ such that $3x^2 + 17x + 15 = 2x^2 + 21x + 12 - 5x^2 + 17x + 34.$
+1908 Alright. First, let's combine all like terms to this horrible mess. We get that
\(6x^{2}-21x-31=0\)
Now, we simply apply the quadratic formula and take the smaller root. Using the fomrula, we get
\(x=\frac{21\pm \sqrt{(-21)^{2}-4\cdot 6(-31)}}{2\cdot 6}\)
From this monstrosity, we get that
\(x=\frac{\sqrt{1185}+21}{12}\\ x=\frac{-\sqrt{1185}+21}{12}\)
Obviously, the first term of x is bigger, so we take that as our answer.
We find that x is \(x=\frac{\sqrt{1185}+21}{12}\)
So our answer is just the biiger root.
Thanks! :)
also, 500th answer...woop woop! :)
