Find the largest value of $x$ such that $3x^2 + 17x + 15 = 2x^2 + 21x + 12 - 5x^2 + 17x + 34.$
Combining all like terms and moving all terms to one side we get
6x2−21x−31=0
Now, we simply use the quadratic equation, we get
x1,2=−(−21)±√(−21)2−4⋅6(−31)2⋅6
x1=−(−21)+√11852⋅6,x2=−(−21)−√11852⋅6
x=21+√118512,x=21−√118512
So our final answers are x=21+√118512,x=21−√118512
Thanks! :)