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(csc(x)*cos(x)) divided by tan(x)+cot(x)

 

thank you!

 Mar 29, 2017
 #1
avatar+130466 
+3

(csc(x)*cos(x)) divided by tan(x)+cot(x)  =

 

[1/sinx) *cos(x)]  /  [ sinx/cosx  + cosx/sinx]  =

 

[  cot x  ]  /    [ (sin^2 x  + cos^2 x )  /  sinx cosx ] =

 

[ cot x ] / [ 1 / sinx cosx ] =

 

[ cot x] [ sin x cos x ]  =

 

[cosx / sin x ] [sin x cos x ]  =

 

cos^2 (x)

 

 

 

cool cool cool

 Mar 29, 2017
 #2
avatar+9488 
+3

cscxcosxtanx+cotx =1sinxcosxsinxcosx+cosxsinx =cosxsinx1sinxcosx+cosxsinx =cosxsinxsinxcosx+sinxcosxsinx =cosxsin2xcosx+cosx =cosxsin2xcosx+cos2xcosx =cosxsin2x+cos2xcosx =cosx1cosx =cos2x

 

:))

.
 Mar 29, 2017

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