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# algebra

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in excerises 14 and 15, find the value of k so that the grap of the equation has the given slope and y-intercept.

14. y=6kx-2; m=2 over 3

15. y= -1 over 2 x + 4 over 3k; b = -8

Dec 11, 2019

#1
+220
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14) i'm going to assume that the slope is 6k. if that's the case, then

6k = 2/3

18k = 2

k = 1/9 :)

15) i'll assume again that your y-intercept is 4/3k. so

4/3k = -8

4 = -24k

-1/4 = k :)

also, i'm assuming you probably aren't the most familiar with what the terms mean in these equations..? so i'll try my best to explain it so i'm not just giving you answers :))

y = mx + b

y and x are the variables that are usually there. i hope that part doesn't need too much explanation

m is the slope, and b is the y-intercept. so in your two equations, in 14, 6k is the slope and -2 is the y-intercept. in 15, -1/2 is the slope and 4/3k is the y-intercept. usually m and b are common variables for defining the slope and y-intercept, respectively. ok i'm done word vomiting, hope this helped!

Dec 11, 2019
#2
+106539
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THX, atlas9    !!!!

CPhill  Dec 11, 2019