Rationalize the following:
1/(sqrt(2) + sqrt(5) + sqrt(7))
Multiply numerator and denominator of 1/(sqrt(2) + sqrt(5) + sqrt(7)) by sqrt(2) - sqrt(5) - sqrt(7):
(sqrt(2) - sqrt(5) - sqrt(7))/((sqrt(2) + sqrt(5) + sqrt(7)) (sqrt(2) - sqrt(5) - sqrt(7)
(sqrt(2) - sqrt(5) - sqrt(7))/((-2 (sqrt(35) + 5)))
((-sqrt(2) + sqrt(5) + sqrt(7)))/(2 (sqrt(35) + 5))
((-sqrt(2) + sqrt(5) + sqrt(7)) (sqrt(35) - 5))/20
((5 sqrt(2) + 2 sqrt(5) - sqrt(70)))/20
+118609 This is how I would do it.
And yes our answers do agree. Thanks guest.
\(\frac{1}{\sqrt{2} + \sqrt{5} + \sqrt{7}}\\ \frac{1}{(\sqrt{2} + \sqrt{5}) + \sqrt{7}}*\frac{(\sqrt{2} + \sqrt{5}) - \sqrt{7}}{(\sqrt{2} + \sqrt{5}) - \sqrt{7}}\\ =\frac{(\sqrt{2} + \sqrt{5} - \sqrt{7})}{(2+5+2\sqrt{10}) -7}\\ =\frac{(\sqrt{2} + \sqrt{5} - \sqrt{7})}{(2\sqrt{10}) }\\ =\frac{(\sqrt{2} + \sqrt{5} - \sqrt{7})}{(2\sqrt{10}) }*\frac{\sqrt{10}}{\sqrt{10}}\\ =\frac{\sqrt{10}(\sqrt{2} + \sqrt{5} - \sqrt{7})}{20}\\ etc \)
You need to check my working for careless errors
