−(2x+1)+4x=13+2(1+5x)
\(\begin{align} −(2x+1)+4x&=13+2(1+5x)\\ [−1(2x+1)]+4x&=13+[+2(1+5x)]\\ [-2x-1]+4x&=13+[2+10x]\\ -2x-1+4&=13+2+10x\\ -1+2x&=15+10x\\ -1+2x\textcolor{blue}{-2x}&=15+10x\textcolor{blue}{-2x}\\ -1&=15+8x\\ -1\textcolor{blue}{-15}&=15+8x\textcolor{blue}{-15}\\ -16&=8x\\ -2&=x\\ x&=-2\\ \end{align} \)
−(2x+1)+4x=13+2(1+5x)
\(\begin{align} −(2x+1)+4x&=13+2(1+5x)\\ [−1(2x+1)]+4x&=13+[+2(1+5x)]\\ [-2x-1]+4x&=13+[2+10x]\\ -2x-1+4&=13+2+10x\\ -1+2x&=15+10x\\ -1+2x\textcolor{blue}{-2x}&=15+10x\textcolor{blue}{-2x}\\ -1&=15+8x\\ -1\textcolor{blue}{-15}&=15+8x\textcolor{blue}{-15}\\ -16&=8x\\ -2&=x\\ x&=-2\\ \end{align} \)