+2653 Find all real values of $s$ such that $x^2 + sx + 144 - 63 + x^2 - 25 - 18$ is the square of a binomial.
+1926 First, let's combine all like terms.
We get \(2x^2+sx+38\)
Dividing everything by 2, we get \(x^2 + \frac{s}{2}x+19\)
Square rooting 19, we get \(\sqrt{19}\)
So, we have \(\sqrt{19}/2 = s/2\)
So \(s=\sqrt{19}\)
Thanks! :)
