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Find all real values of $s$ such that $x^2 + sx + 144 - 63 + x^2 - 25 - 18$ is the square of a binomial.

 Jun 9, 2024
 #1
avatar+1926 
+1

First, let's combine all like terms. 

 

We get \(2x^2+sx+38\)

 

Dividing everything by 2, we get \(x^2 + \frac{s}{2}x+19\)

 

Square rooting 19, we get \(\sqrt{19}\)

 

So, we have \(\sqrt{19}/2 = s/2\)

 

So \(s=\sqrt{19}\)

 

Thanks! :)

 Jun 9, 2024

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