+0  
 
-1
5
1
avatar+1791 

Five workers have been hired to complete a job. If one additional worker is hired, they could complete the job $8$ days earlier. If the job needs to completed $28$ days earlier, how many additional workers should be hired?

 Mar 7, 2024
 #1
avatar+128794 
+1

Let the time to complete the job with 5 workers = T days

 

So......the total man-days for the job  is  5T

 

If one additional worker is  hired, the man-days for the job is 6 (T - 8)

 

So....since the man-days will be the same for the job.....

 

5T  = 6(T - 8)

 

5T = 6T - 48

 

48 = T 

 

So   the number of man-days to complete the job is   5(48)  = 240

 

So.....to complete the job 28 days earlier

 

(number of  workers needed) * ( 48 - 28)  =  240

 

(number of workers needed)  * (20)   = 240

 

number of workers needed  = 240 / 20     =    12

 

So.....(12  - 5) =  7  additional workers should be hired to  complete the job 28 days earlier

 

cool cool cool

 Mar 8, 2024

3 Online Users

avatar
avatar