+0  
 
0
67
4
avatar

Find all pairs of real numbers such that x + y = 10 and x^2 + y^2 = 56 - 2xy.
For example, to enter the solutions and , you would enter "(2,4),(-3,9)" (without the quotation marks).

 Jul 26, 2021
 #1
avatar+34382 
+1

Hmmmmmm....

     x+y = 10    and    (x+y)2 = 56     doesn't seem to have a solution.....am I missing something? cheeky

 Jul 26, 2021
 #2
avatar+24 
+1

Hmm idk if its just me but the first equation cant be simplyfied and for the 2nd one i got it from x^2+y^2=56-2xy -> 2xy+x^2+y^2=56 ->xy+x^2+y^2=24. Now i dont think you can simplify it anymore so..... 

Tr1ck3d  Jul 26, 2021
 #3
avatar+34382 
+1

2xy+x^2+y^2=56 ->xy+1/2 x^2+1/2 y^2=28

ElectricPavlov  Jul 26, 2021
 #4
avatar+114511 
0

Thanks EP

 

Tr1ck if you still have questions or concerns please keep asking .

 

We like interacting with people here   laugh

Melody  Jul 26, 2021

40 Online Users

avatar
avatar
avatar