+656 Will and Grace are canoeing on a lake. Will rows at $50$ meters per minute and Grace rows at $30$ meters per minute. Will starts rowing at $2$ p.m. from the west end of the lake, and Grace starts rowing from the east end of the lake at $2{:}45$ p.m. If they always row directly towards each other, and the lake is $2800$ meters across from the west side of the lake to the east side, at what time will the two meet?
+907 First, let's find how far Will gets before Grace even starts to row.
We have the handy equation \(d=rt\) where d is distance, r is rate, and t is time.
We have \( (45 min)(50 m/min) = 2250 m \), so will paddled 2250m before Grace started.
When Grace starts to canoe, the two have \((2800 m) – (2250 m) = 550 m \) before they meet up.
Thus, we can write the equation
\((50)(t) + (30)(t) = 550 \\ 80t = 550 \\ t = 550/80 = 6.875 \)
This rounds to approximately 6 minutes and 52 seconds.
This means the two spent about \(51:52\) minutes to meet eachother.
This means they met each other at \(2:51:52 pm\)
So 2:51:52 is our final answer.
Thanks! :)
