+1501 Will and Grace are canoeing on a lake. Will rows at $50$ meters per minute and Grace rows at $30$ meters per minute. Will starts rowing at $2$ p.m. from the west end of the lake, and Grace starts rowing from the east end of the lake at $2{:}45$ p.m. If they always row directly towards each other, and the lake is $2800$ meters across from the west side of the lake to the east side, at what time will the two meet?
+1950 First, let's find how far Will gets before Grace even starts to row.
We have the handy equation d=rt where d is distance, r is rate, and t is time.
We have (45min)(50m/min)=2250m, so will paddled 2250m before Grace started.
When Grace starts to canoe, the two have (2800m)–(2250m)=550m before they meet up.
Thus, we can write the equation
(50)(t)+(30)(t)=55080t=550t=550/80=6.875
This rounds to approximately 6 minutes and 52 seconds.
This means the two spent about 51:52 minutes to meet eachother.
This means they met each other at 2:51:52pm
So 2:51:52 is our final answer.
Thanks! :)
