If m is a real number such that m^2 + 1 = 3m, find the value of the expression below.
(m^5 + 2m^3 - 9m + 27)/(m^2 + 1)
+18 Here you go guest:
if m2 + 1 = 3m
we can simplify like this:
(m5+2m3-9m+27)/3m
= (m3(m2+2)-9m+27)/3m
= (m3(3m+1)-9m+27)/3m
= (3m4+(m3-9m)+27)/3m
= (3m4+m(m2-9)+27)/3m
= (3m4+m(3m+10)+27)/3m
= (3m4+3m2+10m+27)/3m
= (3m2(m2+1)+10m+27)/3m
= (3m2(3m)+10m+27)/3m
= (9m3+10m+27)/3m
= (m(9m2+10)+27)/3m
= (m(27m+1)+27)/3m
= (27m2+m+27)/3m
= (27(m2+1)+m)/3m
= (27(3m)+m)/3m
= (81m+m)/3m
=(82m)/(3m)
= 82/3
= 27 1/3
P.S. I probably made a mistake somewhere, but this is the general idea of how to do it!
