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If m is a real number such that m^2 + 1 = 3m, find the value of the expression below.

 

(m^5 + 2m^3 - 9m + 27)/(m^2 + 1)

 Jul 22, 2021
 #1
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Here you go guest:

 

if m2 + 1 = 3m

we can simplify like this:

(m5+2m3-9m+27)/3m

= (m3(m2+2)-9m+27)/3m

= (m3(3m+1)-9m+27)/3m

= (3m4+(m3-9m)+27)/3m

= (3m4+m(m2-9)+27)/3m

= (3m4+m(3m+10)+27)/3m

= (3m4+3m2+10m+27)/3m

= (3m2(m2+1)+10m+27)/3m

= (3m2(3m)+10m+27)/3m

= (9m3+10m+27)/3m

= (m(9m2+10)+27)/3m

= (m(27m+1)+27)/3m

= (27m2+m+27)/3m

= (27(m2+1)+m)/3m

= (27(3m)+m)/3m

= (81m+m)/3m

=(82m)/(3m)

= 82/3

= 27 1/3

angelangelangel

 

P.S. I probably made a mistake somewhere, but this is the general idea of how to do it!

 Jul 23, 2021

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