Find all real values of x such that (x^2 + 2x + 5 - x - 4)(3x^2 - x - 4 + 2x + 8) >= 0
x is every number i think
I agree with that answer as well. Both of the factors will always result in a result greater than or equal to 0.
All values of \(x\) can be solutions.
- Eyedrop
