Find the sum of the squares of the solutions to 2x^2 + 4x - 1 = x^2 - 3x.
if you move things around you will find this is a quadratic, and you will get x^2 + 7x - 1 = 0 (i believe) and then you can simply plug it in to the quadratic formula
is my answer below correct?
Simplifying gives x2+7x−1=0, so the roots are x=−7±√72−4∗1∗−12=−7±√532. (−7+√532)2+(−7−√532)2=51