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# Algebra

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Find the sum of the squares of the solutions to 2x^2 + 4x - 1 = x^2 - 3x.

Aug 19, 2021

#1
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if you move things around you will find this is a quadratic, and you will get x^2 + 7x - 1 = 0 (i believe) and then you can simply plug it in to the quadratic formula

Aug 19, 2021
#3
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Simplifying gives $$x^2 + 7x - 1 = 0$$, so the roots are $$x = {-7 \pm \sqrt{7^2-4*1*-1} \over 2}$$$$= {-7 \pm \sqrt{53} \over 2}$$$$({{-7 + \sqrt{53}} \over 2}) ^2 + ({{-7 - \sqrt{53}} \over 2})^2 = 51$$