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# algebra

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Solve (2x + 4)/(x^2 + 4x - 5) = (2 - x)/(x + 5).

Feb 20, 2021

#1
+944
+1

$$\frac{2x+4}{x^2+4x-5} = \frac{2-x}{x+5}$$

$$(2x+4)(x+5) = (2-x)(x^2+4x-5)$$

$$2(x+2)(x+5) = -(x-2)(x+5)(x-1)$$

$$2(x+2) = -(x^2-3x+2)$$

$$2x+4 = -x^3+3x-2$$

$$x^2 - x + 6 = 0$$

$$\boxed{x = -3, 2}$$

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Feb 20, 2021

#1
+944
+1

$$\frac{2x+4}{x^2+4x-5} = \frac{2-x}{x+5}$$

$$(2x+4)(x+5) = (2-x)(x^2+4x-5)$$

$$2(x+2)(x+5) = -(x-2)(x+5)(x-1)$$

$$2(x+2) = -(x^2-3x+2)$$

$$2x+4 = -x^3+3x-2$$

$$x^2 - x + 6 = 0$$

$$\boxed{x = -3, 2}$$

CubeyThePenguin Feb 20, 2021