What real value of produces the smallest value of the quadratic t^2 - 9t - 36 + 3t^2 - t + 10?
+2668 Simplify it to: \(4t^2-10t-26\)
The least possible value occurs at: \(\large {-b \over 2a} \)
The quadratic equation is in the form \(ax^2+bx+c\) only difference being that we have t instead of x.
Plugging in the values, we have the lowest real value occurs at \(\color{brown}\boxed{5 \over 4}\)
