+864 The parabola y=ax2+bx+c is graphed below. Find a⋅b⋅c. (The grid lines are one unit apart.)
+37165 Vertex at 3,1 and a point on the parabola is 0, 7
Vertex form :
f(x) = d ( x-3)^2 + 1 sub on the point 0,7 to find d = 2/3
so the equation is now
f(x) = 2/3(x-3)^2 + 1 which expands to 2/3 x^2 -4 + 7 so a = 2/3 b = - 4 c = 7 which when multiplied together = -18 2/3
