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The parabola $y = ax^2 + bx + c$ is graphed below. Find $a \cdot b \cdot c.$ (The grid lines are one unit apart.)

 

 Aug 4, 2024
 #1
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Vertex at 3,1    and a point on the parabola is  0, 7 

Vertex form :

   f(x) =  d ( x-3)^2 + 1       sub on the point 0,7   to find  d = 2/3

so the equation is now 

    f(x) = 2/3(x-3)^2 + 1      which expands to    2/3 x^2 -4 + 7      so    a = 2/3       b = - 4    c = 7    which when multiplied together = -18 2/3

 Aug 4, 2024

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