write a equation of a line that passes through (-3, 9) and has a slope of 0
Hey there, Guest!
You want to find the equation for a line that passes through the point (-3,9) and has a slope of 0.
First of all, remember what the equation of a line is:
y = mx+b
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was 0. So you can right away fill in the equation for a line somewhat to read:
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(-3,9). When x of the line is -3, y of the line must be 9.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-3,9).
So, why not plug in for x the number -3 and for y the number 9? This will allow us to solve for b for the particular line that passes through the point you gave!
The equation of the line that passes through the point (-3,9) with a slope of 0
Hope this helped!
( ﾟдﾟ)つ Bye