algebra

y = 9      that's it....

Hey there, Guest!

You want to find the equation for a line that passes through the point (-3,9) and has a slope of 0.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 0. So you can right away fill in the equation for a line somewhat to read:

y=0x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-3,9). When x of the line is -3, y of the line must be 9.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-3,9).

So, why not plug in for x the number -3 and for y the number 9? This will allow us to solve for b for the particular line that passes through the point you gave!

• (-3,9). y=mx+b or 9=0 × -3+b, or solving for b: b=9-(0)(-3). b=9.

The equation of the line that passes through the point (-3,9) with a slope of 0

is

y=+9

Hope this helped!

( ﾟдﾟ)つ Bye