Hi can anyone help me?
How to solve 12345678^4-(12345679^2+1)(12345677^2+1)?
The answer is -4 but whyy?? Thanks so much!:)
123456784−(123456792+1)(123456772+1)
We set x=12345678, so we have x4−[(x+1)2+1]⋅[(x−1)2+1]
x4−[(x+1)2+1]⋅[(x−1)2+1]=x4−[x2+2x+1+1]⋅[x2−2x+1+1]=x4−[x2+2x+2]⋅[x2−2x+2]=x4−[(x2+2)+2x]⋅[(x2+2)−2x]=x4−[(x2+2)2−(2x)2]=x4−[x4+4x2+4−4x2]=x4−[x4+4]=x4−x4−4x4−[(x+1)2+1]⋅[(x−1)2+1]=−4
123456784−(123456792+1)(123456772+1)
We set x=12345678, so we have x4−[(x+1)2+1]⋅[(x−1)2+1]
x4−[(x+1)2+1]⋅[(x−1)2+1]=x4−[x2+2x+1+1]⋅[x2−2x+1+1]=x4−[x2+2x+2]⋅[x2−2x+2]=x4−[(x2+2)+2x]⋅[(x2+2)−2x]=x4−[(x2+2)2−(2x)2]=x4−[x4+4x2+4−4x2]=x4−[x4+4]=x4−x4−4x4−[(x+1)2+1]⋅[(x−1)2+1]=−4