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Hi can anyone help me?

How to solve 12345678^4-(12345679^2+1)(12345677^2+1)?

The answer is -4 but whyy?? Thanks so much!:)

 Aug 19, 2015

Best Answer 

 #1
avatar+26396 
+8

123456784(123456792+1)(123456772+1)

 

 We set x=12345678, so we have x4[(x+1)2+1][(x1)2+1]

 

x4[(x+1)2+1][(x1)2+1]=x4[x2+2x+1+1][x22x+1+1]=x4[x2+2x+2][x22x+2]=x4[(x2+2)+2x][(x2+2)2x]=x4[(x2+2)2(2x)2]=x4[x4+4x2+44x2]=x4[x4+4]=x4x44x4[(x+1)2+1][(x1)2+1]=4

 

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 Aug 19, 2015
 #1
avatar+26396 
+8
Best Answer

123456784(123456792+1)(123456772+1)

 

 We set x=12345678, so we have x4[(x+1)2+1][(x1)2+1]

 

x4[(x+1)2+1][(x1)2+1]=x4[x2+2x+1+1][x22x+1+1]=x4[x2+2x+2][x22x+2]=x4[(x2+2)+2x][(x2+2)2x]=x4[(x2+2)2(2x)2]=x4[x4+4x2+44x2]=x4[x4+4]=x4x44x4[(x+1)2+1][(x1)2+1]=4

 

heureka Aug 19, 2015
 #2
avatar+118696 
0

That is cool Heureka  

 Aug 19, 2015

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