What is the radius of the circle inscribed in triangle ABC if AB = 10, AC = 17, BC = 21? Express your answer as a decimal to the nearest tenth.
Thanks in advance!
Here's a pic, ACG :
The perpendicular bisectors meet at (7, 3.5)......this is the circle's center
The equation of the circle is
(x - 3.5)^2 + ( y - 7)^2 = 3.5^2
So.....the radius is 3.5
Thanks CPhill, unfortunately I can't see your diagram but I think i get the gist!