If $h(x)$ is a function whose domain is $[-8,8]$, and $g(x)=h\left(\frac x2\right)$, then the domain of $g(x)$ is an interval of what width?

So I set $h(x) = \sqrt{64-x^2}$ then $g(x) = \sqrt{64-(x/2)^2}$

Here's a graph https://www.desmos.com/calculator/pmgjsaz6jh

So the width of the interval is 32 right?

Guest Feb 3, 2021