In a bag of candy, the probability that an orange candy is chosen is 0.55 and the probably that a green is chosen is 0.45. A person reaches into the bag of candy and chooses two. If X is the number of green candy pieces chosen, find the probability that has 0, 1, or 2 green pieces chosen.

(a) Draw a tree diagram showing the possibilities for each outcome.

(b) Create the binomial distribution table for .

For A

https://prnt.sc/82ig3ls-ixe3

And for B I could just write 0.45*0.45?

loona Mar 16, 2022

#1**+2 **

Binomial Distribution Table:

Orange-Orange: 0.55 x 0.55 = 0.3025

Orange-Green: 0.55 x 0.45 = 0.2475

Green-Orange: 0.45 x 0.55 = 0.2475

Green-Green: 0.45 x 0.45 = 0.2025

geno3141 Mar 16, 2022

#2**+1 **

Thanks Geno,

Hi Loona,

Firstly this would have to be a bevy big bag of candy (really of infinite size) otherwise it is not correct to do it this way.

But for a school question you do not have to worry about that.

Your question for part B looks unfinished. Maybe some LaTex has been omitted?

Be careful to proofread you questions before you post them.

You made a good start on you tree but in my view it is not finished.

Melody Mar 16, 2022