In a bag of candy, the probability that an orange candy is chosen is 0.55 and the probably that a green is chosen is 0.45. A person reaches into the bag of candy and chooses two. If X is the number of green candy pieces chosen, find the probability that has 0, 1, or 2 green pieces chosen.
(a) Draw a tree diagram showing the possibilities for each outcome.
(b) Create the binomial distribution table for .
And for B I could just write 0.45*0.45?
Binomial Distribution Table:
Orange-Orange: 0.55 x 0.55 = 0.3025
Orange-Green: 0.55 x 0.45 = 0.2475
Green-Orange: 0.45 x 0.55 = 0.2475
Green-Green: 0.45 x 0.45 = 0.2025
Firstly this would have to be a bevy big bag of candy (really of infinite size) otherwise it is not correct to do it this way.
But for a school question you do not have to worry about that.
Your question for part B looks unfinished. Maybe some LaTex has been omitted?
Be careful to proofread you questions before you post them.
You made a good start on you tree but in my view it is not finished.