A box contains 28 red balls, 20 green balls,19 yellow balls, 13 blue balls, 11 white balls, and 9 black balls. What is the minimum number of balls that must be drawn from the box without replacement to guarantee that at least 15 balls of a single color will be drawn?

hellospeedmind Sep 21, 2019

#1**+3 **

Alright, it says to GUARUNTEE

So we are going to find the worst case possible.

Any color balls under 15 will be drawn

So 13 + 11 + 9 = 33

Now we have 28 red, 20 green, 19, yellow.

The worst case possible is 14 from each

14 red, 14 green, and 14 yellow.

So we drew 14 red, 14 green, 14 yellow, and 13 blue, 11 white, 9 black balls.

The next ball we draw NOT MATTER WHAT will make 15 balls of a single color drawn.

So we drawn 14 + 14 + 14 + 13 + 11 + 9 + 1

76 balls should be the answer.

CalculatorUser Sep 21, 2019