An analogue signal is sampled every 160 µs to convert it into a digital representation. What is the corresponding sampling rate expressed in kHz?

According to the Sampling Theorem, for this sampling rate, what will approximately be the highest frequency present in the signal, in kHz, assuming the lowest frequency is very close to zero?

If each sample is quantised into 128 levels, what will be the resulting bitrate in bps?

Give your answer in scientific notation to 2 decimal places.

Hint: you will first need to determine the number of bits per sample that produces 128 quantisation levels.

 Aug 19, 2020

1/160 x 10-6  = 6250 hz    =   6.25 kHz


Not sure about Sampling Theorem but I THINK the highest would be   6.25 kHz/2 = 3.125 kHz  Highest freq in signal


2= 128  so you will need 7 bits to represent

     7 bits x 6.25 x 10samples =   43750 bits per second   =   4.38 x 10bits per second

 Aug 19, 2020

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