an apple cost 3x+6 pesos while an orange cost 4x-5 pesos. what is the total cost of 1 dozen apples and half dozen of orange
$$1\ dozen = 12$$
$$1/2 \ dozen = 6$$
dozen apples + 1/2dozen oranges
(36x+72) + (24x-30)
(36x+24x) + (72-30)
60x + 42
So our answer is 60x + 42 pesos.
If we knew the value of x, we could find the exact cost. We don't though, so this is our final answer.
I suspect x is meant to be the number of items purchased here. That is:
cost of apples = 3*number of apples + 6 pesos.
cost of oranges = 4*number of oranges - 5 pesos
If that is the case then total cost = 3*12 + 6 + 4*6 - 5 = 61 pesos