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an ice cream cone consists of two scoops placed on a cone with the diameter 10 am and height 12cm. the radius of both scoops of ice cream is 4 cm. If the ice cream melts will the cone overflow? if so by how much? Justify your answer.

 Jun 9, 2016

Best Answer 

 #1
avatar+118653 
+5

an ice cream cone consists of two scoops placed on a cone with the diameter 10 am and height 12cm. the radius of both scoops of ice cream is 4 cm. If the ice cream melts will the cone overflow? if so by how much? Justify your answer.

 

Volume of ice cream

\(\mbox{Volume of ice cream}\\ =2\times \frac{4}{3}\times\pi r^3\\ =2\times \frac{4}{3}\times\pi \times 4^3\\ =2\times \frac{4}{3}\times\pi \times 4^3\\ =170\frac{2}{3}\pi \;\;ml\\ =536ml\;\;\mbox{to the nearest ml. That is a lot of ice cream!}\\~\\ \mbox{Volume of cone}\\ =\frac{1}{3}\times\pi r^2\times h\\ =\frac{1}{3}\times\pi \times 5^2\times 12\\ =100\pi \;\;ml\\ =314\;ml\qquad \mbox{To the nearest ml}\\~\\ \)

536-314 = 222

Approx 222ml  will have to flow over the side unless you eat it first.    ://

 Jun 9, 2016
 #1
avatar+118653 
+5
Best Answer

an ice cream cone consists of two scoops placed on a cone with the diameter 10 am and height 12cm. the radius of both scoops of ice cream is 4 cm. If the ice cream melts will the cone overflow? if so by how much? Justify your answer.

 

Volume of ice cream

\(\mbox{Volume of ice cream}\\ =2\times \frac{4}{3}\times\pi r^3\\ =2\times \frac{4}{3}\times\pi \times 4^3\\ =2\times \frac{4}{3}\times\pi \times 4^3\\ =170\frac{2}{3}\pi \;\;ml\\ =536ml\;\;\mbox{to the nearest ml. That is a lot of ice cream!}\\~\\ \mbox{Volume of cone}\\ =\frac{1}{3}\times\pi r^2\times h\\ =\frac{1}{3}\times\pi \times 5^2\times 12\\ =100\pi \;\;ml\\ =314\;ml\qquad \mbox{To the nearest ml}\\~\\ \)

536-314 = 222

Approx 222ml  will have to flow over the side unless you eat it first.    ://

Melody Jun 9, 2016

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