We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

An analogue signal has a bandwidth extending from very low frequencies up to 4 kHz. Using the sampling theorem , what is the minimum sampling rate (number of samples/sec) required to convert this signal into a digital representation?


If each sample is now quantised into 4096 levels, what is the resulting transmitted bit rate, expressing your answer in scientific notation?

Hint: you first need to calculate the number of bits per sample that will produce 4096 quantisation levels 


Thanks for any help

 Mar 12, 2019

I believe if I remember correctly, the sampling rate should be TWICE the highest frequency  ...    so    8 kHz sampling rate.

I'll have to review the second part of your question...

   but maybe each sample will need to be  2^x = 4096     where x is the numer of bits   = 12 bits long

      12 bits / sample   x   8 kHz  = 96000 bits/sec      9.6 x 10^4 bits/sec

 Mar 12, 2019

14 Online Users