Let A = (6,2), and let B be the reflection of A over the line \(y = \frac{1}{2} x + 5\). Find the coordinates of B.
Perpindicular slope to the given line is -2
perpindicular line with the given point 6,2 is y = -2x + 14
Point of intersection of the two lines is 3.6 , 6.8
point equidistant as (6,2) on the other side of the original line = 1.2 , 11.6
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