+0  
 
0
84
1
avatar+221 

What is the area of the portion of the circle defined by \(x^2-12x+y^2=28\) that lies above the \(x\)-axis and to the right of the line \(y=6-x\)?

 Jul 21, 2020
 #1
avatar+27605 
+1

This is a circle centered at 6,0   with aradius of 8

The line goes right through the center ...and has a slope of -1   

     so it forms a 135o angle with the x axis

Total area = pi 8^2

    for the 135 degree portion    135/360 * pi * 82 = 75.4  units2

 

Here  is a picture:

https://www.desmos.com/calculator/kusprk1stg

 Jul 21, 2020

57 Online Users

avatar
avatar