+0  
 
0
69
3
avatar+110 

How do I calculate the are for the interior region formed by \(y =2x -4, y=-3x+16 \)  and the y-axis \(\)

 Jan 29, 2021
 #1
avatar+116126 
+2

A graph works best  :   https://www.desmos.com/calculator/efn1vtgwgr

 

Note  that  this region forms  a triangle with a base of  16 - - 4 =   20

And  the intersection of these lines is (4, 4)   so   the height  of the triangle formed=  4

 

So  the area = (1/2)  base * height   =  (1/2) 20 *  4 =    40 units^2

 

cool cool cool

 Jan 29, 2021
 #2
avatar+110 
+1

 

 

So then if I have y=4x-6, y=-2x+12 and y-axis can I calculate the area to be

 

1/2*b*h where b = 18, h = 3 from the graph so area = 27?

 

Am I approaching this the right way?

 Jan 29, 2021
edited by geoNewbie21  Jan 29, 2021
edited by geoNewbie21  Jan 29, 2021
 #3
avatar+116126 
+1

Let me check

 

Base = 18    height  =  3

 

Correct,  geoNewbie   !!!!

 

 

cool cool cool

CPhill  Jan 29, 2021

44 Online Users

avatar
avatar