What is the area in square units of the convex quadrilateral with vertices (-1, 0), (0, 1), (2, 0) and (0, 3)?
+2668 3.5 sq units
Split the quadrilateral into two triangles using the y-axis as a line. You now have two triangles one with 2x3x1/2 = 3 sq units and 1 with 1 x 1 x1/2 = 0.5 units. Adding these up gives you your area of 3.5 square units
