The area of rectangle ABCD with vertices A(0, 0), B(0, 4), C(x, 4) and D(x, 0) is \(16\) square units. If x > 0, what is the value of x?

Guest Apr 13, 2022

#1**+3 **

From the information given above, we can say that the width of the rectangle is \(4\)

The area of a rectangle is \(length \cdot width\)

That is, \(4 \cdot length = 16\)

That gives us length = \(16/4 = 4\)

From that, we can tell that the value of \(x\) must be \(4\).

Vinculum Apr 13, 2022

#2**+3 **

I'm pretty sure that 4 is the answer, but....hold up

Wouldn't that make it a square though??

Can anyone please confirm?

Vinculum
Apr 13, 2022

#4**+1 **

But, a square is technically a rectangle... So your answer would still be right.

BuilderBoi
Apr 13, 2022