The area of rectangle ABCD with vertices A(0, 0), B(0, 4), C(x, 4) and D(x, 0) is \(16\) square units. If x > 0, what is the value of x?
+580 From the information given above, we can say that the width of the rectangle is \(4\)
The area of a rectangle is \(length \cdot width\)
That is, \(4 \cdot length = 16\)
That gives us length = \(16/4 = 4\)
From that, we can tell that the value of \(x\) must be \(4\).
+580 I'm pretty sure that 4 is the answer, but....hold up
Wouldn't that make it a square though??
Can anyone please confirm?
+2668 But, a square is technically a rectangle... So your answer would still be right.
