What is the area of the region of points satisfying the inequalities x<=0, y<=0, and y>= Ix+4I -8

Guest Apr 21, 2022

#1**+1 **

Look at the graph here : https://www.desmos.com/calculator/em32xqiof4

We can split the area into two triangles....one with a base and height of 4

Area = (1/2)4*4 = 8

And the second one with a base of 16 and a height of 8

Area = (1/2)(16)(8) = 64

The area we are interested in = 64 - 8 = 56

CPhill Apr 21, 2022