What is the area of the region of points satisfying the inequalities x<=0, y<=0, and y>= Ix+4I -8
+128408 Look at the graph here : https://www.desmos.com/calculator/em32xqiof4
We can split the area into two triangles....one with a base and height of 4
Area = (1/2)4*4 = 8
And the second one with a base of 16 and a height of 8
Area = (1/2)(16)(8) = 64
The area we are interested in = 64 - 8 = 56
