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Andrea, Kim and Joy are attemptingto triangulate the locations of their homes for a science and math project. Kim lives 12 blocks away from andrea, Joy lives 7 blocks away from Kim and Andrea lives 15 blocks away from Joy.

 

a. imagine that the houses are in a triangle, and assume that Kim lives the farthest north, Andrea lives the farthest west and Joy lives the farthest east. 

 

find the angles for each part of the triangle

 Aug 19, 2016
 #1
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Label the vertices of the triangle K (Kim), A (Andrea), and J (Joy).

The lengths of the sides of the triangles are:  AK = 12, AJ = 15, and KJ = 7.

 

Since you know the three sides of the triangle, use the Law of Cosines:  c2  =  a2 + b2 - 2·a·b·cos(C).

 

To find angle K:  AJ2  =  AK2 + KJ2 - 2·AK·KJ·cos(K)

--->                    152  =  122 + 72 - 2·12·7·cos(K)   

--->                    225  =  144 + 49 - 168·cos(K)

--->                    225  =  193 - 168·cos(K)

--->                      32  =  -168·cos(K)

--->              -32/168  =  cos(K)

--->                        K  =  cos-1(-32/168)

--->                        K  =  101º  (approximately)

 

To find angle J:  AK2  =  AJ2 + KJ2 - 2·AJ·KJ·cos(J)    (or you can use the Law of Sines)

--->                    122  =  152 + 72 - 2·15·7·cos(J)   

--->                    144  =  225 + 49 - 210·cos(J)

--->                    144  =  274 - 210·cos(J)

--->                   -130  =  -210·cos(J)

--->             130/210  =  cos(J)

--->                        J  =  cos-1(130/210)

--->                        J  =  52º  (approximately)

 

Thus A  =  27º  (approximately)

 Aug 19, 2016

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