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Let AB be a diameter of a circle, and let C be a point on the circle such that AC=8 and BC=4 The angle bisector of ACB intersects the circle at point M Find CM.

 Nov 13, 2022
 #1
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CM = 5*sqrt(11)

 Nov 13, 2022
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The triangle formed by ABC is a right triangle where AB is the hypotenuse which is also the diameter of the circle. But the triangle ACM is an isosceles triangle whose base is CM having 2 sides equal: side AC and AM. Kohl's Feedback Survey

 Nov 14, 2022
edited by Joehollywood  Nov 14, 2022

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