Let AB be a diameter of a circle, and let C be a point on the circle such that AC=8 and BC=4 The angle bisector of ACB intersects the circle at point M Find CM.
+13 The triangle formed by ABC is a right triangle where AB is the hypotenuse which is also the diameter of the circle. But the triangle ACM is an isosceles triangle whose base is CM having 2 sides equal: side AC and AM. Kohl's Feedback Survey
