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In the diagram below, lines \(AB\) and \(ED\) are parallel. Angle \(\angle BCD\) is a right angle and \(\angle CBF = 125^{\circ} \). Find angle \(\angle CDE\)

 

 Sep 14, 2019

Best Answer 

 #1
avatar+1533 
+2

\(\text{We can draw a line from point B to point D to create triangle BCD}\)

\(\text{Notice how angle FBD is 90 degrees with angle FBC of 125 degrees. This means angle DBC is 35 degrees.}\)

 

\(\text{Since the sum of the angles of a triangle is 180, this means angle BDC is 55 degrees}\)

 

\(\text{Now notice how angle BDE is 90 degrees, and we have angle BDC is 55 degrees. That means angle x is }\boxed{35^{\circ}}\)

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 Sep 14, 2019
 #1
avatar+1533 
+2
Best Answer

\(\text{We can draw a line from point B to point D to create triangle BCD}\)

\(\text{Notice how angle FBD is 90 degrees with angle FBC of 125 degrees. This means angle DBC is 35 degrees.}\)

 

\(\text{Since the sum of the angles of a triangle is 180, this means angle BDC is 55 degrees}\)

 

\(\text{Now notice how angle BDE is 90 degrees, and we have angle BDC is 55 degrees. That means angle x is }\boxed{35^{\circ}}\)

CalculatorUser Sep 14, 2019
 #2
avatar+103858 
0

Nice job, CU !!!!

 

 

cool cool cool

CPhill  Sep 14, 2019
 #3
avatar+1533 
+2

thanks!

CalculatorUser  Sep 14, 2019

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