In the diagram below, lines \(AB\) and \(ED\) are parallel. Angle \(\angle BCD\) is a right angle and \(\angle CBF = 125^{\circ} \). Find angle \(\angle CDE\).
+2863 \(\text{We can draw a line from point B to point D to create triangle BCD}\)
\(\text{Notice how angle FBD is 90 degrees with angle FBC of 125 degrees. This means angle DBC is 35 degrees.}\)
\(\text{Since the sum of the angles of a triangle is 180, this means angle BDC is 55 degrees}\)
\(\text{Now notice how angle BDE is 90 degrees, and we have angle BDC is 55 degrees. That means angle x is }\boxed{35^{\circ}}\)
.+2863 \(\text{We can draw a line from point B to point D to create triangle BCD}\)
\(\text{Notice how angle FBD is 90 degrees with angle FBC of 125 degrees. This means angle DBC is 35 degrees.}\)
\(\text{Since the sum of the angles of a triangle is 180, this means angle BDC is 55 degrees}\)
\(\text{Now notice how angle BDE is 90 degrees, and we have angle BDC is 55 degrees. That means angle x is }\boxed{35^{\circ}}\)
