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# angles

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In the diagram below, lines $$AB$$ and $$ED$$ are parallel. Angle $$\angle BCD$$ is a right angle and $$\angle CBF = 125^{\circ}$$. Find angle $$\angle CDE$$ Sep 14, 2019

#1
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$$\text{We can draw a line from point B to point D to create triangle BCD}$$ $$\text{Notice how angle FBD is 90 degrees with angle FBC of 125 degrees. This means angle DBC is 35 degrees.}$$

$$\text{Since the sum of the angles of a triangle is 180, this means angle BDC is 55 degrees}$$

$$\text{Now notice how angle BDE is 90 degrees, and we have angle BDC is 55 degrees. That means angle x is }\boxed{35^{\circ}}$$

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Sep 14, 2019

#1
+2

$$\text{We can draw a line from point B to point D to create triangle BCD}$$ $$\text{Notice how angle FBD is 90 degrees with angle FBC of 125 degrees. This means angle DBC is 35 degrees.}$$

$$\text{Since the sum of the angles of a triangle is 180, this means angle BDC is 55 degrees}$$

$$\text{Now notice how angle BDE is 90 degrees, and we have angle BDC is 55 degrees. That means angle x is }\boxed{35^{\circ}}$$

CalculatorUser Sep 14, 2019
#2
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Nice job, CU !!!!   CPhill  Sep 14, 2019
#3
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thanks!

CalculatorUser  Sep 14, 2019