Calculate angular speed of the 26 inch bicycle rotating at 200 revolutions per minute. Express your answer in radians per minute. Use pi.
+128460 I'm assuming that 20 inches represents the diameter, so 10 inches is the radius
15.5 miles in one hour = 15.5 x 5280 ft = 81840 ft / 60min = 1364 ft/min
And the bike travels [2 * pi * 10] inches = (20 * pi) inches = 62.83 inches in every revolution = about 5.236 ft in every revolution
So.........1364/5.236 = about 260.5 revolutions per minite = 261 revs (rounded)
+128460 Well, if it rotates at 200 revolutions per minute, there are 2pi radians in each revolution....so....it goes through 200 x 2pi = 400pi rads/ min ..... the tire size is irrelevant in terms of angular speed......
at what rate would you have to pedal a 20 inch bike so that it traveled at a linear speed of 15.5 miles per hour? express your answer in revolutions per minute rounded to the nearest whole number. (Hint: first change miles per hour into inches per minute)
+128460 I'm assuming that 20 inches represents the diameter, so 10 inches is the radius
15.5 miles in one hour = 15.5 x 5280 ft = 81840 ft / 60min = 1364 ft/min
And the bike travels [2 * pi * 10] inches = (20 * pi) inches = 62.83 inches in every revolution = about 5.236 ft in every revolution
So.........1364/5.236 = about 260.5 revolutions per minite = 261 revs (rounded)
