+0  
 
+4
713
2
avatar+773 

When the expression 4(x^2-2x+2)-7(x^3-3x+1) is fully simplified, what is the sum of the squares of the coefficients of the terms?

 Jan 4, 2020
 #1
avatar+773 
+10

can someone please answer me.

 Jan 4, 2020
 #2
avatar+36915 
+1

First, expand the terms

 

4x^2-8x+8      - 7x^3 + 21x - 7       now collect 'like' terms

 

-7x^3   +4x^2    - 8x+21x    + 8 - 7       simplify

-7x^3  + 4x^2   + 13x   +` 1              

       now you can see the coeffiicients   ( -7   4    13     and 1  (the constant coefficient) ) ....square them and add them together....

 Jan 4, 2020

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