When the expression 4(x^2-2x+2)-7(x^3-3x+1) is fully simplified, what is the sum of the squares of the coefficients of the terms?
can someone please answer me.
First, expand the terms
4x^2-8x+8 - 7x^3 + 21x - 7 now collect 'like' terms
-7x^3 +4x^2 - 8x+21x + 8 - 7 simplify
-7x^3 + 4x^2 + 13x +` 1
now you can see the coeffiicients ( -7 4 13 and 1 (the constant coefficient) ) ....square them and add them together....