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Quadrilateral $ABCD$ is a square, and segment $AE$ is perpendicular to segment $ED$. If $AE = 8$ units and $DE = 6$ units, what is the area of pentagon $AEDCB$, in square units?

eileenthecoolbean  Jul 14, 2017
 #1
avatar+87564 
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I assume that we have this : 

 

 

Tha area of AEDCB = area of square ABCD + area of triangle AED =

 

10^2  + (1/2) (8) (6)  =

 

100 + 24  =  124  sq units

 

However....if E is in the interior of ABCD the area of AEDCB 100 - 24  = 76 sq units

 

 

cool cool cool

CPhill  Jul 14, 2017
edited by CPhill  Jul 14, 2017

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