Quadrilateral $ABCD$ is a square, and segment $AE$ is perpendicular to segment $ED$. If $AE = 8$ units and $DE = 6$ units, what is the area of pentagon $AEDCB$, in square units?
I assume that we have this :
Tha area of AEDCB = area of square ABCD + area of triangle AED =
10^2 + (1/2) (8) (6) =
100 + 24 = 124 sq units
However....if E is in the interior of ABCD the area of AEDCB 100 - 24 = 76 sq units
+77 
