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Another math problem that can be solved?

 Mar 2, 2019

Best Answer 

 #1
avatar+18346 
+4

Ideal gas law  

 

PV = nRT

P/nR = T/V     in your question's situation   P is consatnt   n is constant and R is the ideal gas constant....so the entire left side of this equation is a constant....let's call it  ' k '

so

 

k = T1/V1  = T2/V2       when dealing with gas laws   T MUST BE IN Kelvin degrees !!!

 

20 C = 273.15 +20  K   = 293.15K

 

soooo....

 

293.15 k / 2L  =  x/ 1L        x is the temp (in Kelvin we are looking for)  

          x = 293.15/2 = 146.58 k          146.58-273.15 =  - 126.58 C

 Mar 2, 2019
 #1
avatar+18346 
+4
Best Answer

Ideal gas law  

 

PV = nRT

P/nR = T/V     in your question's situation   P is consatnt   n is constant and R is the ideal gas constant....so the entire left side of this equation is a constant....let's call it  ' k '

so

 

k = T1/V1  = T2/V2       when dealing with gas laws   T MUST BE IN Kelvin degrees !!!

 

20 C = 273.15 +20  K   = 293.15K

 

soooo....

 

293.15 k / 2L  =  x/ 1L        x is the temp (in Kelvin we are looking for)  

          x = 293.15/2 = 146.58 k          146.58-273.15 =  - 126.58 C

ElectricPavlov Mar 2, 2019
 #2
avatar
+1

Note that temperatures in Kelvin do not use degrees. The unit measure is simply Kelvin(s).

Guest Mar 2, 2019
 #3
avatar+18346 
+2

Correct-a-mundo !    Just hoping to avoid confusion for those learnig the system....    cheeky

ElectricPavlov  Mar 2, 2019

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