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A 4-inch by 6-inch picture is enlarged for framing by tripling its dimensions. A 2-inch-wide border is then placed around each side of the enlarged picture, as shown. Thin metal framing is sold only in increments of one foot. What is the minimum number of linear feet of framing that must be purchased to go around the perimeter of the border?

 

mathbum  Sep 6, 2018

Best Answer 

 #1
avatar+1996 
+2

we start with 4x6 inches and we triple this to become 12x18 inches

 

we can't see what "as shown" is.  I'm going to assume they miter the corners as that is what's usually done.

 

So each piece of framing has to be 4 inches longer than it's associated side.

 

Thus we have 2 framing pieces at 16 inches, and 2 at 22 inches for a total of 76 inches.

 

This is 6 feet 4 inches so we much buy 7 feet of framing.

Rom  Sep 6, 2018
 #1
avatar+1996 
+2
Best Answer

we start with 4x6 inches and we triple this to become 12x18 inches

 

we can't see what "as shown" is.  I'm going to assume they miter the corners as that is what's usually done.

 

So each piece of framing has to be 4 inches longer than it's associated side.

 

Thus we have 2 framing pieces at 16 inches, and 2 at 22 inches for a total of 76 inches.

 

This is 6 feet 4 inches so we much buy 7 feet of framing.

Rom  Sep 6, 2018

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