A train is 1/4 miles long and travels at a constant speed of 8 miles per hour. A boy on a bicycle, traveling at a constant speed of 11 miles per house, rides on a road next to the track. From the moment he passes the rear of the train, it takes him m minutes to reach the front. Find m
I've never really got how to do these types of problems so it would be appreciated if someone could kinda help guide me through this
Ill see if I can do this in like 11 hours its like 10:30 pm for me so i gotta sleep
boy is going 11mph train is 8mph so boy is 3mph faster and so the time for a 3mph object to move 1 mile is 20m and so to move 1/4 a mile is 20/4 which is 5m
Difference in speed is 11- 8 = 3 m/hr
to cover 1/4 mile : 1/4 m / 3 m/hr = 1/12 hr = 5 mins.