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A train is 1/4 miles long and travels at a constant speed of 8 miles per hour. A boy on a bicycle, traveling at a constant speed of 11 miles per house, rides on a road next to the track. From the moment he passes the rear of the train, it takes him m minutes to reach the front. Find m 

 

I've never really got how to do these types of problems so it would be appreciated if someone could kinda help guide me through this

thanks! 

 Dec 21, 2021
 #1
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Ill see if I can do this in like 11 hours its like 10:30 pm for me so i gotta sleep

 Dec 21, 2021
 #2
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The answer is 6 minutes.

 Dec 21, 2021
 #3
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boy is going 11mph train is 8mph so boy is 3mph faster and so the time for a 3mph object to move 1 mile is 20m and so to move 1/4 a mile is 20/4 which is 5m

 Dec 21, 2021
 #4
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Difference in speed is   11- 8 = 3 m/hr

 

to cover 1/4 mile    :      1/4 m / 3 m/hr = 1/12 hr = 5 mins.

 Dec 21, 2021
 #5
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These questions are so fun. Let me know if you need helpwith any more

 Dec 30, 2021

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