An ant is on the face of a cube with edges measuring five centimeters. The ant starts one centimeter from an edge and two centimeters from another, and wishes to travel to a point on an edge one centimeter from the farthest vertex. What is the shortest distance he can walk along the surface of the cube to accomplish this?
This is from a little compilation of problems I found online.. not sure how to solve!!
If you use 1+1+1−−−−−−−−√1+1+1, the answer is drilling straight through the cube.
(What a talented ant UwU)
However, we need the ant to go in a path on the surface of a cube, which poses new challenges.
We can quickly visualize the ant going up the cube while going around to the other side.
This, is a straight line along the 1×21×2 rectangle formed by the path.
Therefore, the shortest length is 12+22−−−−−−√=5–√12+22=5.
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