An ant is on the face of a cube with edges measuring five centimeters. The ant starts one centimeter from an edge and two centimeters from another, and wishes to travel to a point on an edge one centimeter from the farthest vertex. What is the shortest distance he can walk along the surface of the cube to accomplish this?
This is from a little compilation of problems I found online.. not sure how to solve!!
If you use 1+1+1−−−−−−−−√1+1+1, the answer is drilling straight through the cube.
(What a talented ant UwU)
However, we need the ant to go in a path on the surface of a cube, which poses new challenges.
We can quickly visualize the ant going up the cube while going around to the other side.
This, is a straight line along the 1×21×2 rectangle formed by the path.
Therefore, the shortest length is 12+22−−−−−−√=5–√12+22=5.
If you need a more in debt just ask!
-wolfie
That does not seem to be one of the answer choices. I forgot to include the answer choices with my post, here they are:
A) 8 B)10 C) 3√7 D)9 E)√65