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So, I have to solve for 't' in this equation:

 

x=x0+v0t+1/2at2

 

And, I can't deal with it. Somebody help?

 Jul 23, 2017

Best Answer 

 #1
avatar+27578 
+1

It's a quadratic in t.  

 

Rewrite it as  1/2at2 +v0t+x0-x=0   

 

Multiply by 2/a:    t2 +(2v0/a)t +2(x0-x)/a = 0

 

Use the quadratic formula:

 

t = { -(2v0/a) + sqrt[ (2v0/a)2 - 4*2(x0-x)/a) ] }/2    → { -v0 + sqrt[ v02 - 2a(x0-x) ] }/a

 

(Because t is almost certainly time here, we don't need to look at the other solution)

 Jul 23, 2017
edited by Alan  Jul 23, 2017
 #1
avatar+27578 
+1
Best Answer

It's a quadratic in t.  

 

Rewrite it as  1/2at2 +v0t+x0-x=0   

 

Multiply by 2/a:    t2 +(2v0/a)t +2(x0-x)/a = 0

 

Use the quadratic formula:

 

t = { -(2v0/a) + sqrt[ (2v0/a)2 - 4*2(x0-x)/a) ] }/2    → { -v0 + sqrt[ v02 - 2a(x0-x) ] }/a

 

(Because t is almost certainly time here, we don't need to look at the other solution)

Alan Jul 23, 2017
edited by Alan  Jul 23, 2017

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