The quadratic function d(s) -0.0065s^2 + 0.14s models the relationship between the stopping distance, d, in metres and speed,s, in kilometres per hour in a driving car. What is the fastest you can drive and still be able to stop within 60m?
You are given d=60 find s by using the equation
But I think there is a typo in your equation...I will answer with an = rather than a minus sign
60 = - .0065 s^2 + .14s
0 = - .0065 s^2 + .14s -60 Use quadratic formula to find s = imaginary numbers
something is wrong with your equation as you typed it..... if I use d in km I get 21.1kilometers/hr which I think is incorrect too
Please proofread your question...... is 's' really km/hr ? Is d really meters ? Is the equation correct?
If the equation is d = .0065s^2 + .14s THEN I get s = 85.9 kilometers /hr