The quadratic function d(s)= -0.0056s^2 + 0.14s models the relationship between the stopping distance, d, in metres and speed,s, in kilometres per hour in a driving car. What is the fastest you can drive and still be able to stop within 60m?
Did you post the other incorrect version of this ????????
d = 60 find s
60 = -.0056s^2 + .-14s
-.0056s^2 + .14s - 60 = 0 Quadrtaic Formula yields s = still yields imaginary numbers
if you drop the negative sign in front of the s^2 you will get s = 91.76 km/hr
( the other incorrect posting of this question had - .0065 s^2 this one (also incorrect) has - .0056s^2 )